## Friday, November 30, 2012

Question:

### nearest hundredth of a meter.

Solution:

Hope this helps :)! Let's do better next test guys :D !

## Thursday, November 29, 2012

### Symmetry

Symmetry

Definition of Symmetry:
When both sides are identical

Definition of Line of Symmetry
The line that divides the image into two identical shapes

The three lines of symmetry are:
- Horizontal
- Vertical
- Oblique

Transformation
is when a geometric shape moves.

These are the types of Tranformation:
- Rotation
- Translation
- Reflection

Translation- is when you move an object on a straight line.

It can be describe in;
- Words
- Abbreviated
- Symbols

## Wednesday, November 28, 2012

### Symmetry

Define Symmetry :
is when the shape is reflected and becomes exactly image.

Define Line of Symmetry :
The line that divides the image in 2 identical halves.

The 3 types are:

1. Horizontal
2. Vertical
3. Oblique
Example:
purple- horizontal
red- vertical
green and yellow- oblique
Red- vertical
Blue and purple- oblique
Green- horizontal
NO lines.
Transformation :
is when a geometric shape moves.

This can include:
1. reflection
2. translation
3. rotation

Translation- is when you move an object on a straight line.

It can be describe in;
- words
- abbreviated ( R4, D2 )
- symbols ( -->  , <-- )

### Textbook pg 81 #34

Use the formula  r√ A / π to determine the radius of a circular garden with an area of 40m². Express your answer to the nearest tenth of a metre.

## Question 24:

The distance, d, in kilometres, that a person can see across the ocean to the horizon is given by the formula d = square root of 12.74 x h. In the formula h is the height, in metres, of the person's eyes above the water. Calculate the distance that each of the following people can see across the horizon. Express each answer to the nearest tenth of a kilometre.

c) Yvonne is the pilot of an aircraft flying 5 km above the coastline.

## Answer:

252.4 km is the distance that Yvonne can see across the horizon.

## Saturday, November 24, 2012

### Textbook pg.81 #32

The answer is 35.7 cm

## Thursday, November 22, 2012

### Textbook pp. 80 Question 24.A) Ashton V.

Math Textbook pp. 80 Question 24.a

24. The distance , d, in kilometres, that a person can see across the ocean to the horizon is given by the formula d= the square root of of 12.74 x h. In the formula h= Height, in metres, of the person's eyes above the water. Calculate the distance that each of the folloeing people can see across the ocean to the horizon. Express each answer to the nearest tenth of a kilometre.

A) Adele is sitting on a lifeguard station at the edge of the ocean. Her eyes are 4.1m above the water.
--------------------------------------------------------------------------------------------------------------------------

that is how i found my awnser. ==>(Sorry if you can't read my writing)<==

The distance that Adele can see across the ocean to the horzion is 7.2 kilometres.

### Textbook Page 80 Question #28

Question: The period, t, in seconds, of a pendulum is the time it take for a complete swing back and forth. The period can be calculated from the length, l, in metres, of the pendulum using the formula t = *square root* of 41. Determine the period of a pendulum with each of the following lengths. Express each answer to the nearest hundredth of a second

A) 1.6 m

l = 1.6 m
t = *square root* 4l
t =  *square root* 4(1.6
t = *square root* 6.4
t = 2.529

Round to nearest hundredth of a second: 2.53 s.

B) 2.5 m

l = 2.5 m
t = *square root* 4l
t = *square root* 4(2.5)
t = *square root* 10
t = 3.1622

Round to nearest hundredth of a second: 3.16 s.

C) 50 cm

l = 50 cm
t = *square root* 4l
t = *square root* 4(0.5)  << To get 0.5, you change 50 into a decimal, 50 divided by 100 gives you 0.5
t = *square root* 2
t = 1.414

Round to nearest hundredth of a second: 1.41 s.

## Wednesday, November 21, 2012

### Knowledge and Understanding

Explain why the solution to 2/5 x +3=1/2 is equivalent to the solution of 4x + 30 = 5

equation 1             equation 2
2/5 = 0.4                4
+3                          +30
1/2=0.5                  =5

equation 2 is equivalent to equation 1 because all the numbers for equation 2 are up one place value
the answer will always be the same throughout place values

x= -6.25

40x + 300 = 50 is equivalent to the other equations

### Textbook Page 79 Question 16

Page 16.

a) The label on a 1-L can of paint states that the paint will cover an area of 10m squared. What is the side length of the largest square area that the paint will cover? Express your answer to the nearest hundreth of a metre.
﻿﻿﻿﻿﻿

The side length of the area that the paint will cover is 3.16 metres.

b) What is the side length of the largest square area that a 3.79-L can of the same paint will cover? Express your answer to the nearest hundreth of a metre.

The side length that a 3.79-L can of paint can cover is 6.16 metres.

c) Nadia is applying two coats of the paint to an area that is 4.6m by 4.6m. How much paint will she use if she applies the same amount of paint for each coat? Express your answer to the nearest tenth of litre. (SORRY ABOUT THE NECK BREAKER)

She will need 4.2 litres of paint for the two coats.

### Textbook: Chapter 2.4 pg 81 Question #36

36. Determine √65536

-√65536 - perfect square because 256 x 256 = 65536

-√256 - perfect square because 16 x 16 = 256

-√16 - perfect square because 4 x 4 = 16

- The answer for √65536 is 4 because:

-Since there are three square root sign, you have to square root the given number three times.

~√65536
~√256
~√16 = 4

### Textbook question #35

The width of  a rectangle is 1/3 it's length. The Area of the rectangle 9.72 m2, what are the dimensions of the rectangle.

To do this question first you need to find the length of the rectangle. To get the length you can just compute the square root and then divide it by 1/3.
5.4 cm is the length of the rectangle now to find the width of the rectangle it says the the width is 1/3 the length so to get the width you just multiply 1/3 by 5.4cm and you will get the width.

5.4 x 1/3= 1.8cm

The whole dimension of the rectangle is 1.8cm by 5.4cm

## Tuesday, November 20, 2012

### Page 79, Question 18 by Jay Jay Ladesma

18. A frame measures 30 cm by 20 cm. Can you mount a square picture with an area of 500 cm2 in the frame? Explain

No because the square root of 500 cm is 22.36068 therefore, each side of the picture is 22.36 cm and it is too big for the frame because it is only 30 cm by 20 cm.

### Page 81, question number 31 A

V=square root

31. The area of a triangle can be determined using Heron's formula, which requires the side lengths of the triangle. Heron's formula is A=Vs(s-a)(s-b)(s-c). In the formula A is the area; a, b, and c are the side lengths; and s is half the perimeter or a+b+c/2.

Determine the area of each triangle with the following side lengths. Express each area to the nearest tenth of a square centimeter.
A) 15cm, 12cm, 10cm
B) 9.3cm, 11.4cm, 7.5cm

A= Vs(s-a)(s-b)(s-c)
A= Area
a, b, c= side lengths
S= Half of the perimeter

15+12+10=37
=37/2
=18.5

V 18.5(18.5-15)(18.5-12)(18.5-10)

V 18.5(3.5)(6.5)(8.5) V 18.5(22.75)(8.5) V 18.5(193.375) V 3577.4375 =59.81168364If you round off 59.81168364 to the nearest tenth, it would be 59.8cm.

A) 15cm, 12cm, 10cm is the right answer.

### Question 23

A rectangle floor that measures 3 m by 2 m covered by 384 square tiles. Determine the side length of each tile, in centimetres. State any assumptions you make.

3m = 300cm
2m = 200cm

l x w = A
300 x 200 = 60 000cm2
60 000cm2 / 384 = 156.25cm2

1 tile = 156.25cm2

√156.25cm2 = 12.5cm2

Each side length of the square is 12.5cm2
All 384 square tiles are 12.5cm2

## Solve for the variable

### Math Textbook pg. 80 #27

Question :
The surface area of a cube is 100 cm2. Determine the edge length of the cube to the nearest tenth of a centimeter.

Answer:
100 cm2 = 10 000
10 000/6 = 1 666.6666....
1 666.6666...= 40.8 cm2

40.8 cm2 = 1 664.64
1 664.64*6 = 9 987.84
9 987.84 = 99.9 cm2

The length of one edge of the cube is approx. 40.8 cm2

This  website helped me a lot with this question.

### Math Textbook Pg.80 #24 b.

The Distance, d, in kilometers, that a person can cross the ocean to the horizon is given by formula  d = /12.4 x h. in the formula h is the height, in meter of the persons eye above the waters. Calculate the distance to each of the following people can see across the ocean to the horizon . Express answer to the nearest tenth of a kilometer.

B)  Brian is standing at the water's edge. His eyes are 165 cm above the water.

### Math Textbook Pg 80 #30

A video on knowing how to Square Root

### Textbook Pg.79 #20

Leon's rectangular living room is 8.2m by 4.5m. A square rug covers 2/5 of the area of the floor. What is the side length of the rug, to the nearest tenth of a metre?

 The side length of the rug would be 3.8m.

### Textbook PAGE 80 #@^(26) Terence Guanzon

A bag of fertilizer will cover an area of 200m2. Determine the dimensions of a square that 3/4 of a bag of fertilizer will cover. Express your answer to the nearest tenth of a metre.
200m2=
200x200= 40 000
40 000 / 3/4=
40 000 / 75= 533.333...
533.333... / 2x2x2= 66.666...
66.666... / 5= 13.333...
13.333... >>>>>> 12m?

### Textbook pg.80, #21

21. A baseball diamond is a square area of about 750m². What is the distance from first to second base. Give your answer to the nearest tenth of a meter.

## Monday, November 19, 2012

### Math Notes- November 19,2012

To determine perfect squares and surds.

I noticed that the surds have an odd number of decimals. (Notice the red line on the picture above). If it is a perfect square, it would have an even amount of decimals.
for example:
√0.0081 = 0.09²

There is an even amount of decimals (in this case, there are

four) which tells me that it's square root is not a surd.

SQUARE ROOT OF FRACTIONS:

### Solution:

#### ANSWER:  Kai needs 1.3m laminate.

### Homework Handout page -12

QUESTION- Philip knows that a pyramid has a height of 6 m and volume 900 m cubed. He  determines the area of base as.

V= 1/3 ( area of base) ( height)
900= 1/3 ( area of base) (6)
900/3= ( area of base ) (6)

300-6= area of base

- Area of base of pyramid is 294 m.
prove that this is incorrect and state Philip's error.

ANSWER-

To find the volume of a pyramid given by the formula is:
Volume of pyramid =  Area of base × height
What Philip did wrong according to the formula
of how to find  volume of a pyramid is:

1.) He divided 900 by 3 instead of dividing it by 1/3
2.) He took 300 and subtracted 6 instead of dividing 300 by

This is how I think this question should be solved=

1.) 900
----     = Area of Base x 6
1/3
2700 = Area of Base x 6
2700
-----   = Area of  base
6

450 m squared = Area of Base

This is how I think Philip should have done this problem.
So basically you divide the volume by 1/3, then you take that answer and divide it by the height. That is how you will find the area of the base of a pyramid.

Link to help you out-
http://www.onlinemathlearning.com/volume-formula.html

http://www.youtube.com/watch?v=oYGvNlaxnbw

http://www.youtube.com/watch?v=E_2KbL2orfc